7m^2+14=861

Solution for 7m^2+14=861 equation:

7m^2+14=861

We move all terms to the left:

7m^2+14-(861)=0

We add all the numbers together, and all the variables

7m^2-847=0

a = 7; b = 0; c = -847;
Δ = b2-4ac
Δ = 02-4·7·(-847)
Δ = 23716
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{23716}=154$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-154}{2*7}=\frac{-154}{14}
=-11
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+154}{2*7}=\frac{154}{14}
=11
$